Question

tg13π/6-sin(-5π/3)
Решите пожалуйста

Answer 1

tg13π/6-sin(-5π/3)=tg(2π+π/6)+sin (5π/3)=tg(π/6)+sin(6π/3-π/3)=
=(√3)/3+sin(2π-π/3)=(√3)/3+sin(-π/3)=(√3)/3-(√3)/2=-(√3)/6

Answer 2

Спасибо

Answer 3

Net za čto. Do cvidanija!