Question

$y {3} + 6 ^{2} + 9y = 0$
пж​

Answer 1

Ответ:

$y3 + 6 {}^{2} + 9y = 0 \\ 3y + 6 {}^{2} + 9y = 0 \\ 12y + 36 = 0 \\ 12y = - 36 \\ y = - 3$