Question

$x^{3} -8$
c$c ^{3} +27$
$x^{3} + 27y ^{3}$
$-27 x^{3} -8 y^{3}$
$64 x^{6} +27 y^{3}$
$(a-3) ^{3} +64$

Answer 1

$x^{3} -8=(x-2)(x^2+2x+4) \ c ^{3} +27=(c+3)(c^2-3c+9) \ x^{3} + 27y ^{3}=(x+3y)(x^2-3xy+9y^2)$

$-27 x^{3} -8 y^{3}=-(3x+2y)(9x^2-6xy+4y^2) \ 64 x^{6} +27 y^{3}=(4x^2+3y)(16x^4-12x^2y+9y^2) \ (a-3) ^{3} +64=(a-3+4)((a-3)^2-4(a-3)+16)= \ =(a+1)(a^2-6a+9-4a+12+16)=(a+1)(a^2-10a+37)$