Question

$(x - 1) ^{3} - x(x + 2) ^{2} + x(7x - 5) = 6$
помогите!!!!!!!!!!!!!!!!!!!!​

Answer 1

Ответ:

$x = -\frac{7}{6}$

Объяснение:

$(x - 1)x^{3} - x(x + 2)x^{3} + x(7x - 5) = 6$$(x - 1)^{3} - x(x + 2)^{2} + x(7x - 5) = 6\\x^{3} -3x^{2} +3x-1-x(x^{2} +4x+4)+7x^{2} -5x=6\\x^{3} -3x^{2} +3x-1-x^{3}-4x^{2} -4x+7x^{2} -5x=6\\0-6x-1=6\\-6x-1=6\\-6x=6+1\\-6x=7\\x=-\frac{7}{6}$