Question

$\sqrt{c} + \frac{1}\sqrt d} \\ c=0,36 d=0,16$

Answer 1

$\sqrt{c}+\frac{1}{\sqrt{d}}=\sqrt{0,36}+\frac{1}{\sqrt{0,16}}=0,6+\frac{1}{0,4}=\frac{1,24}{0,4}=3,1$

$P.S.:0,6^2=0,36\\\\0,4^2=0,16$