Question

$sqrt[4]{xsqrt{xsqrt[3]{x} } } }$

при х=  $sqrt[5]{27^{4} }$

Answer 1

$sqrt[4]{ sqrt{x^2*x sqrt[3]{x} } } = sqrt[8]{x^3 sqrt[3]{x} }= sqrt[24]{x^9*x} =$$sqrt[24]{x ^{10} } = sqrt[12]{x^5} = sqrt[12]{( sqrt[5]{x ^{12} } )^5} = sqrt[12]{x ^{12} } =x$