Question

$sqrt[4]{x+8}- sqrt[4]{x-8} =2$

Answer 1

$sqrt[4]{x+8}-sqrt[4]{x-8}=2\ sqrt[4]{x+8}=2+sqrt[4]{x-8}\ x+8=(2+sqrt[4]{ x-8})^4\ 8*(x-8)^frac{3}{4}+24*(x-8)^frac{2}{4}+32*(x-8)^frac{1}{4}=0\ (x-8)^frac{1}{4}=t\ 8*t^3+24t^2+32t=0\ 8t^2+24t+32=0\ t=0\ x=8$