Question

$left { {{3 ^{x+y} =27} atop {(x-y) ^{2} =1}} right.$

Answer 1

$left { {{3^{x+y}=27} atop {(x-y)^2=1}} right. \ left { {{3^{x+y}=3^3} atop {(x-y)^2=1}} right. \ left { {{x+y=3} atop {(x-y)^2=1}} right. \ left { {{x=3-y} atop {(3-y-y)^2=1}} right. \ left { {{x=3-y} atop {3-2y=б1}} right. \ left { {{x=3-y} atop {y= frac{3б1}{2} }} right. \ \ \ left { {{x=3-y} atop {y=1 }} right. \ left { {{x=3-y} atop {y=2 }} right. \ \ \ left { {{x=2} atop {y=1 }} right. \ left { {{x=1} atop {y=2 }} right. \ \ OTBET:(1;2),(2;1)$