Ответы на вопрос
Ответил Dимасuk
0
ОДЗ:
2x + 4 ≠ 0
2x ≠ -4
x ≠ -2
![x^2 + 4x = 126(2x + 4) \ \
x^2 + 4x = 252x + 504 \ \
x^2 - 248x - 504 = 0 \ \
x^2 - 248x + 15376 - 15880 = 0 \ \
(x - 124)^2 - (2 sqrt{3970})^2 = 0 \ \
(x - 124 - 2 sqrt{3970} )(x - 124 + 2 sqrt{3970} ) = 0 \ \
x = 124 + 2 sqrt{3970} and x = 124 - 2 sqrt{3970}](https://tex.z-dn.net/?f=x%5E2+%2B+4x+%3D+126%282x+%2B+4%29+%5C+%5C+%0Ax%5E2+%2B+4x+%3D+252x+%2B+504+%5C+%5C+%0Ax%5E2+-+248x+-+504+%3D+0+%5C+%5C+%0Ax%5E2+-+248x+%2B+15376+-+15880+%3D+0+%5C+%5C+%0A%28x+-+124%29%5E2+-+%282+sqrt%7B3970%7D%29%5E2+%3D+0+%5C+%5C+%0A%28x+-+124+-+2+sqrt%7B3970%7D+%29%28x+-+124+%2B+2+sqrt%7B3970%7D+%29+%3D+0+%5C+%5C+%0Ax+%3D+124+%2B+2+sqrt%7B3970%7D+++++++++and+++++++x+%3D+124+-++2+sqrt%7B3970%7D "x^2 + 4x = 126(2x + 4) \ \
x^2 + 4x = 252x + 504 \ \
x^2 - 248x - 504 = 0 \ \
x^2 - 248x + 15376 - 15880 = 0 \ \
(x - 124)^2 - (2 sqrt{3970})^2 = 0 \ \
(x - 124 - 2 sqrt{3970} )(x - 124 + 2 sqrt{3970} ) = 0 \ \
x = 124 + 2 sqrt{3970} and x = 124 - 2 sqrt{3970}")
2x + 4 ≠ 0
2x ≠ -4
x ≠ -2
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