Question

$\frac{(x-1)^2}{5} - \frac{x+4}{6} = \frac{2x-2}{3}$

Answer 1

$\frac{(x-1)^2}{5} - \frac{x+4}{6} = \frac{2x-2}{3} \\ 6(x-1)^2-5(x+4)=10(2x-2) \\ 6(x^2-2x+1)-5x-20=20x-20 \\ 6x^2-12x+6-5x-20=20x-20 \\ 6x^2-37x+6=0 \\ D=1369-144=1225 \\ x_1=\frac{37-35}{12}=\frac{1}{6} \ \ \ \ \ \ \ \ \ \ x_2=\frac{37+35}{12}=6$