Question

$frac{5}{x}$ = 2- $frac{3}{x-2}$

Answer 1

$OD3:\begin{cases}xneq0\xneq2end{cases}$
$frac{5}{x}=2-frac{3}{x-2}\frac{5}{x}-frac{2x-7}{x-2}=0\frac{-x^2+6x-5}{x(x-2)}=0\-x^2+6x-5=0\x^2-6x+5=0\begin{cases}x_1+x_2=6\x_1*x_2=5end{cases}\x_1=5 ;x_2=1$