Question

$frac{3}{x + 2} + frac{2}{x - 2} = frac{13}{ {x}^{2} - 4}$
помогите решить за баллы

Answer 1

$frac{3}{x+2} +frac{2}{x-2} =frac{13}{x^2-4} ;xneq -2;xneq 2\ \3(x-2)+2(x+2)=13\ \ 3x-6+2x+4=13\ \ 5x=15\ \OTVET :x=3$

Answer 2

https://znanija.com/task/31725559 25 б

Answer 3

$frac{3}{x + 2} + frac{2}{x - 2} = frac{13}{ {x}^{2} - 4} ; : x neq -2, : x neq 2\ \ frac{3}{x + 2} + frac{2}{x - 2} = frac{13}{ {x}^{2} - 4} = 0 \ \ frac{3}{x + 2} + frac{2}{x - 2} - frac{13}{(x - 2)(x + 2)} = 0 \ \ frac{3(x - 2) + 2(x + 2) - 13}{(x - 2)(x + 2)} = 0 \ \ frac{3x - 6 + 2x + 4 - 13}{(x - 2)(x + 2)} = 0 \ \ frac{5x + 15}{(x - 2)(x + 2)} = 0 \ \ 5x - 15 = 0 \ \ 5x = 15 \ \ x = 15 div 5 \ \ x = 3; : x neq -2, : x neq 2$