Question

$- \frac{2c ^{2} }{9d ^{3}} \div \frac{8c ^{3} }{27d} =$
памагите пожалуйста решит дию ​

Answer 1

$\displaystyle\bf\\-\frac{2c^{2} }{9d^{3} } :\frac{8c^{3} }{27d}=-\frac{2c^{2} }{9d^{3} }\cdot\frac{27d}{8c^{3} } =-\frac{2c^{2} }{9d\cdot d^{2} } \cdot\frac{9d\cdot 3}{2c^{2} \cdot 4c}=-\frac{3}{4cd^{2} }$