Question

$f frac{1}{3}$(6x-y)=-3
-2(x-3y)=20
Решите систему уравнений

Answer 1

$left { {{ frac{1}{3} (6x-y)=-3} atop {-2(x-3y)=20}} right.$
$left { {{2x- frac{y}{3}=-3 } atop {-2x+6y=20}} right.$
$6y- frac{y}{3} =17$
$18y-y=51$
$17y =51$
$y = 3$
$-2x+18 =20$
$-2x = 2$
$x=-1$