Question

$5^{log5^{2}}+log_7 7$

Answer 1

Формулы: $log_aa=1$ и $log_ab=frac{log_ca}{log_cb}$, $a^{log_ab}=b$

$5^{log5^{2}}+log_7 7=(5^frac{1}{log_510})^{2}+1=(5^{log_510})^{-2}+1=frac{1}{100}+1=frac{101}{100}=1.01$

Answer 2

$5^{log_52}=2$

$log_77=1$

$5^{log5^{2}}+log_7 7$=2+1=3