Question

$2 {x }^{2} - 4x + 1 = 0$
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Answer 1

Ответ:

$2x {}^{2} - 4x + 1 = 0 \\ x = \frac{ - ( - 4) + - \sqrt{(4) {}^{2} - 4 \times 2 \times 1 } }{2 \times 2} \\ x = \frac{4 + - \sqrt{16 - 8} }{4} \\ x = \frac{4 + - \sqrt{8} }{4} \\ x = \frac{4 + - 2 \sqrt{2} }{4} \\ x1 = \frac{2 - \sqrt{2} }{2} \\ x2 = \frac{2 + \sqrt{2} }{2}$

Легко.