Question

$1. y^{'} = ( frac{cos 5x}{ln x})^{'}$

Answer 1

$y'=(frac{cos5x}{lnx})'= frac{-5sin5xcdot lnx-cos5xcdot frac{1}{x}}{ln^2x}= frac{-5xsin5xcdot lnx-cos5x}{xcdot ln^2x}$