Question

$(1- log_{19} 25)(1- log_{5} 95)$

Answer 1

$(1-log_{19}25)(1-log_{5}95)=(1-frac{1}{log_{25}19})(1-log_{5}95)\\ (1-frac{2}{log_{5}19})(1-log_{5}(19*5))=(1-frac{2}{log_{5}19})*-log_{5}19=\\ -log_{5}19+2=2-log_{5}19$