Question

$1)5x^{2}-4x=0\2)5x^{2}-6x+1=0$

Answer 1

1)

$5x^2-4x=0\x*(5x-4)=0\x=0; 5x-4=0\x=0; 5x=4\x=0; x=0,8$

2)

$5x^2-6x+1=0\D=b^2-4ac=36-4*5=16=4^2\x_1=frac{6-4}{2*5} =0,2\x_2=frac{6+4}{2*5} =1$