Question

 

$0,125*2^{4x-16} = (frac{0.25}{sqrt{2}})^{-x}$

 

 решите пожалуйстааа

Answer 1

0,125*2^(4x-16)=(0,25/sqrt2)^(-x)

2^(-3)*2^(4x-16)=(4*sqrt2)^x

2^(4x-19)=2^(2,5x)

4x-19=2,5x

1,5x=19

x=19*(2/3)

x=38/3

x=12,(6)