Question

(t-6)^2-t(t-3) при t=13/3

Answer 1

(t-6)²-t(t-3)=t²-12t+36-t²+3t=-9t+36=[$t= frac{13}{3}$]=$-frac{9*13}{3} +36=-36+36=0$
Ответ:0