Question

Срочно! Заранее спасибо!
Найти производную функции

Answer 1

Ответ:

$1)y' = 3 {e}^{x} + {3}^{x} \times ln(3)$

$2)y' = \frac{(2x - 1)(x - 4) - ( {x}^{2} - 3x)}{ {(x - 4)}^{2} } = \frac{2 {x}^{2} - 8x - x + 4 - {x}^{2} + 3x }{ {(x - 4)}^{2} } = \frac{ {x}^{2} - 6x + 4 }{ {(x - 4)}^{2} }$

$3)y' = 3 {e}^{3x}$

$4)y' = 3 {(5x + 2)}^{2} \times 5 = 15 {(5x + 2)}^{2}$

$5)y' = - ln(2) \times {2}^{x}$

$6)y' = 2(1 - 3x) \times ( - 3) = - 6(1 - 3x) = 18x - 6$

$7)y' = \frac{1}{2} {(2x + 7)}^{ - \frac{1}{2} } \times 2 = \frac{1}{ \sqrt{2x + 7} }$

$8)y' = \frac{1}{3} {(4x - 6)}^{ - \frac{2}{3} } \times 4 = \frac{4}{3 \sqrt[3]{ {(4x - 6)}^{2} } }$