Question

СРОЧНО!!!
Вычислите:
$(3 log_{7}2- log_{7}24) : ( log_{7}3 + log_{7}9 )$

Answer 1

$(3log_72-log_7{24}):(log_73+log_79)=\\=(3log_72-log_7(8cdot 3)):(log_73+log_73^2)= \\=(3log_72-(log_72^3+log_73)):(log_73+2log_73)=\\=(3log_72-3log_72-log_73):(3log_73)= frac{-log_73}{3log_73} =-frac{1}{3}$

Answer 2

(log₇ 2³ - log₇ 24) : (log₇ (3*9))=log₇ (8/24) : log₇ 27=

=log₇ (1/3) : log₇ 3³ = log₇ 3⁻¹ : 3log₇ 3= -log₇ 3 : 3log₇ 3= -1/3