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Ответил zhenyaM2002
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(√6 + √3) *√12 - 2√6 * √3 =
= √(6²*2 ) + √36 - 2√(3²*2) =
= 6√2 + 6 - 6√2 = 6
![( frac{6}{y^2-9} + frac{1}{3-y} ) * frac{y^2 + 6y + 9}{5} = \ \
= ( frac{6}{(y-3)(y+3)} - frac{1}{y-3} ) * frac{y^2+2*3y+3^2}{5} = \ \
= frac{6-(y+3)}{(y-3)(y+3)} * frac{(y+3)^2}{5} = frac{6-y-3}{(y-3)(y+3)} * frac{(y+3)^2}{5}= \ \
= frac{-(y-3)*(y+3)^2}{(y-3)(y+3)*5} = frac{-(y+3)}{5} = - frac{y+3}{5} = \ \
= - frac{1}{5} *(y+3) = -0.2(y+3) = -0.2y -0.6](https://tex.z-dn.net/?f=%28+frac%7B6%7D%7By%5E2-9%7D++%2B++frac%7B1%7D%7B3-y%7D+%29+%2A++frac%7By%5E2+%2B+6y+%2B+9%7D%7B5%7D+%3D++%5C++%5C+%0A%3D+%28+frac%7B6%7D%7B%28y-3%29%28y%2B3%29%7D+-++frac%7B1%7D%7By-3%7D+%29+%2A++frac%7By%5E2%2B2%2A3y%2B3%5E2%7D%7B5%7D+%3D+%5C++%5C+%0A%3D++frac%7B6-%28y%2B3%29%7D%7B%28y-3%29%28y%2B3%29%7D++%2A++frac%7B%28y%2B3%29%5E2%7D%7B5%7D+%3D++frac%7B6-y-3%7D%7B%28y-3%29%28y%2B3%29%7D+%2A+frac%7B%28y%2B3%29%5E2%7D%7B5%7D%3D+%5C++%5C+%0A%3D++frac%7B-%28y-3%29%2A%28y%2B3%29%5E2%7D%7B%28y-3%29%28y%2B3%29%2A5%7D+%3D++frac%7B-%28y%2B3%29%7D%7B5%7D+%3D+-++frac%7By%2B3%7D%7B5%7D+%3D+%5C++%5C+%0A%3D+-+frac%7B1%7D%7B5%7D+%2A%28y%2B3%29+%3D+-0.2%28y%2B3%29+%3D+-0.2y+-0.6 "( frac{6}{y^2-9} + frac{1}{3-y} ) * frac{y^2 + 6y + 9}{5} = \ \
= ( frac{6}{(y-3)(y+3)} - frac{1}{y-3} ) * frac{y^2+2*3y+3^2}{5} = \ \
= frac{6-(y+3)}{(y-3)(y+3)} * frac{(y+3)^2}{5} = frac{6-y-3}{(y-3)(y+3)} * frac{(y+3)^2}{5}= \ \
= frac{-(y-3)*(y+3)^2}{(y-3)(y+3)*5} = frac{-(y+3)}{5} = - frac{y+3}{5} = \ \
= - frac{1}{5} *(y+3) = -0.2(y+3) = -0.2y -0.6")
= √(6²*2 ) + √36 - 2√(3²*2) =
= 6√2 + 6 - 6√2 = 6
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