Question

Срочно третье ПОМОГИТЕ!!!

Answer 1

$frac{2x}{4 {x}^{2} - 1} - frac{x + 4}{2 {x}^{2} + x} = \ = frac{2x}{(2x - 1)(2x + 1)} - frac{x + 4}{x(2x + 1)} = \ = frac{2 {x}^{2} - (x + 4)(2x - 1)}{x(2x - 1)(2x + 1)} = \ = frac{2 {x}^{2} - (2 {x}^{2} - x + 8x - 4) }{x(2x - 1)(2x + 1)} = \ = frac{4 - 7x}{x(2x - 1)(2 + 1)}$