Question

Срочно, решите пожалуйста!

Answer 1

Ответ:

Объяснение:

1)

$\frac{3x^{2} }{7x} =\frac{3x^{2-1} }{7}=\frac{3x}{7}\\\frac{8y^{3} }{15y^{4}} = \frac{8 }{15y^{4-3}}= \frac{8 }{15y}\\\frac{4z^{2} }{-8z^{3} } =\frac{4 }{-4*2z^{3-2} } = \frac{1 }{-2z }\\\frac{x}{y} \frac{2a^{5}}{a^{4}} = \frac{2a^{5-4}}{1} =2a\\\frac{-14b^{2} }{21b^{4} } = \frac{-7*2 }{7*3b^{4-2} } = \frac{-2 }{3b^{2} } \\\frac{27c^{6}}{45c} = \frac{9*3c^{6-1}}{9*5} = \frac{3c^{5}}{5}$

2)

$\frac{3a+3b}{5(a+b)} = \frac{3(a+b)}{5(a+b)} = \frac{3}{5} \\\frac{7x-14y}{3x-6y} = \frac{7(x-2y)}{3(x-2y)}  = \frac{7}{3} \\\frac{5a-20c}{15ac} = \frac{5(a-4c)}{5*3ac} = \frac{a-4c}{3ac}\\\frac{x-2b}{x^{2} -2bx} = \frac{x-2b}{x(x -2b)} = \frac{1}{x}$

3)

$\frac{5x-10}{x^{2}-4 } = \frac{5(x-2)}{(x-2)*(x+2)} = \frac{5}{x+2} \\\frac{a^{2}-9}{15+5a} = \frac{(a-3)*(a+3)}{5(a+3)} = \frac{(a-3)}{5}\\\frac{x^{2} -4x+4}{3x-6}  = \frac{(x-2)^{2}}{3(x-2)}= \frac{(x-2)}{3}\\\frac{b^{2} +6b+9}{b^{2} -9} = \frac{(b+3)^{2}}{(b-3)*(b+3)} = \frac{(b+3)}{(b-3)}$