Question

Срочно решение!!!!!!!!!!

Answer 1

$frac{1}{2}log_{4}7+log_{4} 32-frac{1}{2}log_{4}28=log_{4}sqrt{7}+log_{4}32-log_{4}sqrt{28}=log_{4}(frac{sqrt{7}*32 }{sqrt{4*7} })=log_{4}(frac{sqrt{7}*32 }{2sqrt{7}})=log_{4}16=2$