Question

Срочно пж решить системы
1)(8x+3>0
<
(4x-1>/=0
2) (4-(3x+3)<2(x+1)
<
(3x-1>\=0

Answer 1

$1) \ \displaystyle\left \{ {{8x+3>0} \atop {4x-1\geq 0}} \right. \\\\\\\displaystyle\left \{ {{8x>-3} \atop {4x\geq 1}} \right. \\\\\\\displaystyle\left \{ {{x>-0,375} \atop {x\geq 0,25}} \right. \ \Rightarrow \ \boxed{x\in\Big[0,25 \ ; \ \infty\Big)}\\\\\\\\2) \ \displaystyle\left \{ {{4-(3x+3)<2(x+1)} \atop {3x-1\geq 0}} \right. \\\\\\\displaystyle\left \{ {{4-3x-3<2x+2} \atop {3x\geq 1}} \right. \\\\\\\displaystyle\left \{ {{-5x<1} \atop {3x\geq 1}} \right.$

$\displaystyle\left \{ {{x>-0,2} \atop {x\geq \dfrac{1}{3} }} \right. \ \Rightarrow \ \boxed{x\in\Big[\dfrac{1}{3} \ ; \ +\infty)}$