Question

Срочно пожалуйста!!!!!!!!!!
r1=2 r2=3 r3=4 r4=5 r5=2 r6=6

Answer 1

Ответ:

Объяснение:

r34 = R3*R4 / (R3+R4) = 4*5 / (4+5) ==2.2 Ом

r234 = R2+r34 = 3+2.2 = 5.2  Ом

r56 = R5*R6 / (R5+R6) = 2*6 / (2+6) = 1.5 Ом

r23456 = r234*r56 / (r234 + r56) = 5.2*1.5 / (5.2+1.5) ==1. Ом

R = R1+r23456 = 2+1 = 3 Ом

U = I*R= 7*3 = = 21 B

I1 = I = 7 A

U1 = I1*R1 = 7*2 = 14 B

U5=U6 = U - U1 = 21 - 14 = 7 B

I5 = U5/R5 = 7 / 2 == 3,5 A

I6 = U6/R6 = 7 / 6 ==1.2 A

I2 = U5 / r234 = 7/5.2 = 1.3 A

U2 = I2*R2 = 1.3*3 = 3,9 B

U3=U4 = U5-U2 = 7-3,9 = 3,1 B

I4 = U4/R4 = 3,1 / 5 = 0,6 A

I3 = U3 / R3 = 3,1 / 4 = = 0,8 A

P4 = I4*U4 = 0.6*3.1 ==2 Вт.