Question

Срочно помогите решить.

Answer 1

1)
$sqrt{3} times sqrt{12} = sqrt{3 times 12} = sqrt{36} = 6$
2)
$( sqrt{19} - sqrt{6} ) times ( sqrt{19} + sqrt{6} ) = ( sqrt{19} )^{2} - ( sqrt{6} )^{2} = 19 - 6 = 13$
3)
$frac{ sqrt{24} }{ sqrt{6} } = sqrt{ frac{24}{6} } = sqrt{4} = 2$
4)
$sqrt{8} + 2 sqrt{2} = 2 sqrt{2} + 2 sqrt{2} = 4 sqrt{2}$