Алгебра, вопрос задал mustafaevamubina10 , 1 год назад

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Ответы на вопрос

Ответил сок111213
2

1)

12 \frac{5}{6}  + 2 \frac{7}{9}  \times (15 \frac{9}{10}  - 12 \frac{9}{10} ) =21 \frac{1}{6}   \\ 1) \: 15 \frac{9}{10}  -  12 \frac{9}{10}  = 3 \\ 2) \: 2 \frac{7}{9}  \times 3 =  \frac{25 \times 3}{9}  =  \frac{25}{3}  = 8 \frac{1}{3}  \\ 3) \: 1 2\frac{5}{6}  + 8 \frac{1}{3}  = 12 \frac{5}{6}  + 8 \frac{2}{6}  = 20 \frac{7}{6}  = 21 \frac{1}{6}

2)

5 \frac{7}{16}  \times 1 \frac{3}{29}  + 2 \frac{5}{16}  \times 2 \frac{2}{7}  =  \frac{87 \times 32}{16 \times 29}  +  \frac{37 \times 16}{16 \times 7}  = 6 +  \frac{37}{7}  =  \\  = 6 + 5 \frac{2}{7}  = 11 \frac{2}{7}

3)

(2022 \frac{3}{5}  - 2021 \frac{1}{6} ) \times 1 \frac{1}{29}  = (2022 \frac{18}{30}  - 2021 \frac{5}{30} ) \times 1 \frac{1}{29}  =  \\  = 1 \frac{13}{30}  \times 1 \frac{1}{29}  =  \frac{43 \times 30}{30 \times 29}  =  \frac{43}{29}  = 1 \frac{14}{29}

4)

 \frac{7}{10}  + (1 \frac{1}{3}  -  \frac{2}{9} ) \div 1 \frac{2}{9}  + 2 \frac{1}{2}  \times ( \frac{1}{3}  +  \frac{1}{6} ) = 2 \frac{189}{220}  \\ 1) \: 1 \frac{1}{3}  -  \frac{2}{9}  = 1 \frac{3}{9}  -  \frac{2}{9}  = 1 \frac{1}{9}  \\ 2) \: 1 \frac{1}{9}  \div 1 \frac{2}{9}  =  \frac{10 \times 9}{9 \times 11}  =  \frac{10}{11}  \\ 3) \:   \frac{1}{3}  +  \frac{1}{6}  =  \frac{2}{6}  +  \frac{1}{6}  =  \frac{3}{6}  =  \frac{1}{2}  \\ 4) \: 2 \frac{1}{2}  \times  \frac{1}{2}  =  \frac{5}{2 \times 2}  =  \frac{5}{4}  = 1 \frac{1}{4}  \\ 5) \:  \frac{7}{10 }  +  \frac{10}{11}  + 1 \frac{1}{4}  =  \frac{154}{220}  +  \frac{200}{220}  + 1 \frac{55}{220}  =  \\  = 1 \frac{409}{220}  = 2 \frac{189}{220}

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