Question

Срочно
(е^0,2+3^х)'

Answer 1

1)=e^(0,2x)*0,2+3^x *ln3

2)=3/x+(1/((2x+1)ln5)) *2

3)=e^(4-3x) *3+(1/(2-3x)) *(-3)=3e^(4-3x)-3/(2-3x)

4)=5^(x^2)*ln5*2x+e^((x-4)/5)*(1/5)

5)=-2sin3x*3-4cos(2x+1)*2=-6sin3x-8cos(2x+1)

6)=e^(1-2x)*(-2)*cosx+e^(1-2x)*(-sinx)=e^(1-2x)(-2cosx-sinx)

7)=(e^(0,5x)*0,5*sinx-e^(0,5x)*cosx)/(cosx)^2