Question

СРОЧНО!!!
2x²-7x-4=0

Answer 1

$\displaystyle 2x^2-7x-4=0\\2x^2+x-8x-4=0\\x(2x+1)-4(2x+1)=0\\(2x+1)(x-4)=0\\2x+1=0,x-4=0\\\\x_1=-\frac{1}{2}=-0,5;x_2=4$