Question

Сравните значения a и b, если
a=0,8^2 - 0,2^ , b= (0,8 - 0,2)^2

Answer 1

$a=0.8^2 - 0.2^ 2\ \ a = (0.8 - 0.2)(0.8 + 0.2) = \ = 0.6 times 1 = 0.6 \ \ b= (0,8 - 0,2)^2 \ b = {0.8}^{2} - 2 times 0.8 times 0.2 + {0.2}^{2} = 0.64 - 0.32 + 0.04 = \ = 0.36 \ \ a = 0.6 \ b =0 .36 \ \ 0.6 > 0.36 \ a > b$