Question

Составьте сюжетную задачу: 42/17-х-40/17+х=1​

Answer 1

$frac{42}{17 - x} - frac{40}{17 + x} = 1 \ frac{42}{17 - x} - frac{40}{17 + x} - 1 = 0 \ frac{42(17 + x) - 40(17 - x) - (17 - x) times (17 + x)}{(17 - x)(17 + x)} = 0\ frac{714 + 42x - 680 + 40x - ( {17}^{2} - {x}^{2} )}{(17 - x)(17 + x)} = 0 \ frac{714 + 42x - 680 + 40x - {17}^{2} + {x}^{2} }{(1 7- x)(17 + x)} = 0 \ frac{34 + 82x - 289 + {x}^{2} }{(17 - x)(17 + x)} = 0 \ - 255 + 82x + {x}^{2} = 0 \ {x}^{2} + 82x - 255 = 0 \ x = frac{ - 82 frac{ + }{ - } sqrt{ {82}^{2} - 4 times 1 times ( - 255)} }{2 times 1} \ x = frac{ - 82 frac{ + }{ - } sqrt{6724 + 1020} }{2} \ x = frac{ - 82 frac{ + }{ - } sqrt{7744} }{2} \ x = frac{ - 82 frac{ + }{ - } 88}{2} \ x = frac{ - 82 - 88}{2} \ x = frac{ - 82 + 88}{2} \ x = 3 \ x = - 85 \ x1 = - 85 \ x2 = 3$