Question

сократите дробь 4x^2-16x+12/4x-4

Answer 1

 4x^2-16x+12          4 (x-3) (x-1)         
---------------------- = ---------------------- = x-3
    4x-4                      4 (x-1)  
            
х^2-4х+3=0
D=b^2-4ac=(-4)^2-4*1*3=16-12=4
VD = V4=2
х1=4+2/2=6/2=3
х2=4-2/2=2/2=1

4x^2-16x+12=4(x-3)(x-1)