Question

Sistema de ecuacion no lineal X+y=1
Xy=-6

Answer 1

$left {{x+y=1} atop {xy=-6}} right. ; left { {{y=1-x} atop {x(1-x)=-6}} right. ; left { {{y=1-x} atop {x^2-x-6=0}} right. ; left { {{y=1-x} atop {x_1=-2; ,; x_2=3}} right. ; left { {{y_1=3; ,; y_2=-2} atop {x_1=-2; ,; x_2=3}} right. \\Otvet:; ; (-2,3); ,; ; (3,-2); ,$

Answer 2

$left { {{x+y=1} atop {xy=6}} right. \left { {{xy=-6} atop {x=1-y}} right. \left { {(1){(1-y)*y=-6} atop {x=1-y}} right. \1)(1-y)*y=-6\y-y^{2} +6=0\y^{2} -y-6=0\D=1*1-(-6*4)=25=5^{2} \Y1=(1+5)/2=3\Y2=(1-5)/2=-2\left { {{y=3} atop {x=-2}} right. \left { {{y=-2} atop {x=3}} right.$