Question

|sinx|=2cosx - (корень из 3)cosx

Answer 1

|sinx|= 2cosx - √3cosx

1) sinx ≥ 0

sinx = 2cosx - √3cosx

sinx = cosx (2 - √3)

cosx ≠ 0

tg x = 2 - √3

x₁ = arctg ( 2 - √3) + πn,   n∈Z

1) sinx ≤ 0

-sinx = 2cosx - √3cosx

-sinx = cosx (2 - √3)

cosx ≠ 0

tg x = -(2 - √3)

x₂ = -arctg ( 2 - √3) + πn,   n∈Z

Answer 2

Ответ: X2=-arctg (2- √3)+πn,  n∈Z