Question

sin4x+sin^2x
можно подробней пожалуйста

Answer 1

2sin2xcos2x-sin2x=0

sin2x=0

x=Пk/2

cos2x=1/2

x=+-П/6+Пk

Answer 2

sin4x = 2sin2хcos2x = 2(sixcosx)( cos^2к - sin^2х )
2(sinxcosx) ( cos^2к - sin^2х ) + sin^2x