Question

sin x/2 < - корень 3/2

Answer 1

,..,........,...,..............

Answer 2

Ответ: -2π/3+2πn<х/2<-π/3+2πn; n∈Z;

Объяснение:

sin(x/2) < -√(3/2);

-π-arcsin(-√(3/2))+2πn<х/2<arcsin(-√(3/2))+2πn; n∈Z;

-π+arcsin(√(3/2))+2πn<х/2<arcsin(-√(3/2))+2πn; n∈Z;

-π+π/3+2πn<х/2<-π/3+2πn; n∈Z;

-2π/3+2πn<х/2<-π/3+2πn; n∈Z;