Question

Sin^2x - 3sinx cosx = 1
Срочно!!!!

Answer 1

$sin^2x-3sin xcos x=1\ \ sin^2x-3sin xcos x=sin^2x+cos^2x\ \ cos^2x+3sin xcos x=0\ \ cos x(cos x+3sin x)=0\ \ left[begin{array}{ccc}cos x=0\ tgx=-1/3end{array}right~~~Rightarrow~~~~ left[begin{array}{ccc}x= frac{pi}{2}+ pi n,n in mathbb{Z}\ \ x=-arctg1/3+ pi n,n in mathbb{Z} end{array}right$