Question

sin^2π/6 +cos^2 π/3 t+g^3 3π/4

Answer 1

$sin ^{2}\frac{\pi}{6}+cos^{2} \frac{\pi}{3} +tg^{3} \frac{3\pi}{4}\\( \frac{1}{2})^{2}+ (\frac{1}{2})^{2} +(-1)^{3}= \frac{1}{4}+ \frac{1}{4}-1= -\frac{1}{2} =-0,5$