Question

s(t)=12t-3t^3, t=3
f(x)-2-x^2, x0=-3

Answer 1

S(t)=12t-3t^3, t0=3 
S'(t)=12-9t^2
s'(t0)=12-9*9=12-81= -69
f(x)=2-x^2, x0=-3
f'(x)=-2x
f'(x0)=-2*(-3)=6