Question

решите уровнение х^2-7 [х] +12=0​

Answer 1

Ответ:

${x}^{2} = { |x| }^{2} \\ {x}^{2} - 7x = 12 \\ {x}^{2} - 7x = - 12 \\ d1 = 49 - 4 \times - 12 = 97 > 0 \\ x1 = 7 - \sqrt{97} \div 2 = \frac{7 - \sqrt{97} }{2} \\ x2 = \frac{7 + \sqrt{97} }{2} \\ d2 = 49 - 4 \times 12 < 0$