Question

решите уравнения
(3-x)(x+4)+x2=0
(4-x)(x+5)+x2=0

Answer 1

(3-x)(x+4)+x^2=0
3x-x^2+12-4x+x^2=0
x=12
(4-x)(x+5)+x^2=0
4x-x^2+20-5x+x^2=0
x=20