Question

Решите уравнение x(x^2+4x+4)=3(x+2)

Answer 1

$x(x^2+4x+4)=3(x+2)\x(x+2)^2=3(x+2)\x(x+2)^2-3(x+2)=0\left(x+2right)left(xleft(x+2right)-3right)=0\x+2=0Rightarrow boxed{x_1=-2}\x(x+2)-3=0\x^2+2x-3=0\D_1=1^2-1cdot(-3)=4\x_2=-1-2Rightarrow boxed{x_2=-3}\x_3=-1+2Rightarrow boxed{x_3=1}$

Ответ: -3; -2; 1