Question

решите уравнение (x-4)(2степени)=x(2cтепени)-16

Answer 1

(х-4)$^{2}$ = $x^{2}$ -16
$x^{2}$ - 8х + 16 = $x^{2}$ - 16
$x^{2}$ -8х + 16 - $x^{2}$ + 16 = 0
-8х + 32 = 0
х = 32/8 
х = 4

Answer 2

(x-4)^2=x^2-16
x^2-8x+16-x^2+16=0
-8x+32=0
32=8x
x=32/8
x=4