Question

Решите уравнение
x^3+4x^2=4x+16

Answer 1

$x^{2}(x + 4) - 4(x + 4)=0 (x - 2)(x + 2)(x + 4) = 0 x = -4; -2; 2$

Answer 2

$x^{3} +4 x^{2} =4x+16 \ x^{3} +4 x^{2} -4x-16=0 \ x^{2} (x+4)-4(x+4)=0 \ (x^{2} -4)(x+4)=0 \ (x-2)(x+2)=0 \ x-2=0 \ x_{1} =2 \ x+2=0 \ x_{2} =-2 \ x+4=0 \ x_{3} =-4$