Question

решите уравнение (x+2)^2/2-x^2-4/4-(x-2)^2/8=x^2/8

Answer 1

4(х+2)²-2(х²-4)-(х-2)² = х²
4х²+16х+16-2х²+8-х²+4х-4-х² = 0
20х+20 = 0
20х = -20
х = -20:20
х = -1