Question

решите уравнение f(x+2)=f(x-2)+4, если f(x)=3+2x+x^2

Answer 1

$3 + 2x + 4 +{x}^{2} + 4x + 4 = 3 + 2x - 4 + {x}^{2} - 4x + 4 + 4$
$8x = - 4$
$x = - 0.5$

Answer 2

$f(x) = 3 + 2x + {x}^{2} \ f(x + 2) = 3 + 2(x + 2) + {(x + 2)}^{2} = 3 + 2x + 4 + {x}^{2} + 4x + 4 = {x}^{2} + 6x + 11 \ f(x - 2) = 3 + 2( x - 2) + {(x - 2)}^{2} = 3 + 2x - 4 + {x}^{2} - 4x + 4 = {x}^{2} - 2x + 3 \ {x}^{2} + 6x + 11 = {x}^{2} - 2x + 3 + 4 \ {x}^{2} - {x}^{2} + 6x + 2x + 11 - 3 - 4 = 0 \ 8x + 4 = 0 \ 8x = - 4 \ x = - frac{1}{2}$